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Inquiries on creating tasks

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Klarijon

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Message 2106 - Posted: 14 Sep 2020, 9:19:12 UTC

In recent days, I have been studying the properties of the equation m^n+h=0 (mod n) for m,n \in N, and h \in Z, and I wanted to find the factors of 2^n+1 where n satisfies 2^n+1=0 (mod n) and n>=2187. Is it possible to create new tasks to factor these numbers, and if so, where can I do so?
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Greg
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Message 2107 - Posted: 16 Sep 2020, 18:19:20 UTC - in response to Message 2106.  

No, numbers of that size are well beyond the capabilities of SNFS. You should focus on other factoring methods like ECM.
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